2y^(1/2)-3y^(1/4)=1

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Solution for 2y^(1/2)-3y^(1/4)=1 equation:


D( y )

y < 0

y < 0

y in <0:+oo)

2*y^(1/2)-(3*y^(1/4)) = 1 // - 1

2*y^(1/2)-(3*y^(1/4))-1 = 0

2*y^(1/2)-3*y^(1/4)-1 = 0

t_1 = y^(1/4)

2*t_1^2-3*t_1^1-1 = 0

2*t_1^2-3*t_1-1 = 0

DELTA = (-3)^2-(-1*2*4)

DELTA = 17

DELTA > 0

t_1 = (17^(1/2)+3)/(2*2) or t_1 = (3-17^(1/2))/(2*2)

t_1 = (17^(1/2)+3)/4 or t_1 = (3-17^(1/2))/4

t_1 = (3-17^(1/2))/4

y^(1/4)-((3-17^(1/2))/4) = 0

1*y^(1/4) = (3-17^(1/2))/4 // : 1

y^(1/4) = (3-17^(1/2))/4

( (3-17^(1/2))/4 < 0 i 1/4 in (0:1) ) => y należy do O

t_1 = (17^(1/2)+3)/4

y^(1/4)-((17^(1/2)+3)/4) = 0

1*y^(1/4) = (17^(1/2)+3)/4 // : 1

y^(1/4) = (17^(1/2)+3)/4

y^(1/4) = (17^(1/2)+3)/4 // ^ 4

y = ((17^(1/2)+3)^4)/256

y = ((17^(1/2)+3)^4)/256

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